Remove and Repeat Digit Pattern

The program must accept an integer N as the input. For each digit D in N, the program must print the digit D for X times where X is formed by removing the digit D from the integer N as the output.

Note: The value of N is always not a multiple of 100.

Boundary Condition(s):
101 <= N< 10^5

Input Format:
The first line contains N.

Output Format:
The lines contain the integers separated by a space.

Example Input/Output 1:
Input
121
Output
111111111111111111111
22222222222
111111111111

Explanation
For the first digit in 121, the value of X is 21. So 1 is printed for 21 times. For the second digit in 121, the value of X is 11. So 2 is printed for 11 times. For the third digit in 121, the value of X is 12. So 1 is printed for 12 times.

Example Input/Output 2:
Input:
210
Output:
2222222222
11111111111111111111
000000000000000000000

#include<stdio.h> 
#include<stdlib.h>

int main()
{
	int n;
	scanf("%d",&n); 
	int a[1000000];
	int k=0; 

//storing each element in a array
	while(n>0)
	{
		a[k]=n%10; 
		n/=10; 
		k++;
	}
	int m=k-1;
	k--; 
	int f;
	while(m>=0)
	{
		f=0; 

//calculating the number without its position
		for (int i=k;i>=0; i--)
		{
			if(i!=m) 
			f=(f*10)+a[i];
		}

//printing the digit 
		for (int i=0;i<f;i++) 
		printf("%d ",a[m]); 
		printf("\n");
		m--;
	}
}