String Characters Interlace

Given an input string S, accept the input string S and print the string in the interlaced order as shown in the example Input/Output section.

Input Format:
The first line contains the value of String S (may contain letters, white spaces, special characters, and numbers).

Output Format:
The string S has to be printed in the order of 1st character and (N-1) character, 2nd character and (N-2) character and so on where N is the length of the string S.

Boundary Conditions:
1 <= Length of S <= 100

Example Input/Output 1:
Input:
abc321

Output:
a 1 b 2 c 3

Example Input/Output 2:
Input:
pqrs-wxyz

Output:
p z q y r x s w –

import java.util.*;
public class Hello
 {
    public static void main(String[] args)
 {
    Scanner s=new Scanner(System.in);
String str=s.nextLine();
char ch[]=str.toCharArray();
int f=1,g=0,l=ch.length;
char c[]=new char[l];
for(int i=0;i<l;i++)
{
    if(i%2==0)
    {
    c[i]=ch[i-g];
    g++;
    }
    else
    {
    c[i]=ch[l-f];
    f++;
    }
}
for(int i=0;i<l;i++)
System.out.print(c[i]+" ");
    }
}

def main():
    # Input a string from the user
    str_input = input()

    # Convert the string into a list of characters
    ch = list(str_input)

    # Initialize variables f, g, and l
    f, g, l = 1, 0, len(ch)

    # Create a new list c with None values, same length as the input list ch
    c = [None] * l

    # Manipulate characters in the input string and store them in list c
    for i in range(l):
        if i % 2 == 0:
            c[i] = ch[i - g]
            g += 1
        else:
            c[i] = ch[l - f]
            f += 1

    # Print the modified characters in list c, separated by spaces
    for i in range(l):
        print(c[i], end=" ")

if __name__ == "__main__":
    main()