Positive or Negative Based Multiples

Accept an integer A as the input. If A is a positive integer then print the first five multiples of the unit digit of A as the output. If A is a negative integer then print the first ten multiples of the unit digit of A as the output.

Example Input/Output 1:
Input:
46

Output:
6 12 18 24 30

Example Input/Output 2:
Input:
-53

Output:
3 6 9 12 15 18 21 24 27 30

#include <stdio.h>
int main()
{
    int num, ctr, value;
    scanf("%d", &num);
    if(num > 0)
    {
        value = num % 10;
        for(ctr = 1; ctr <= 5; ctr++)
        {
            printf("%d ", value * ctr);
        }
    }
    else
    {
        value = (num % 10) * (-1);
        for(ctr = 1; ctr <= 10; ctr++)
        {
            printf("%d ", value * ctr);
        }
    }
}

import java.util.*;

public class Hello {

    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int num = sc.nextInt();
        int ctr, value;
        if (num > 0) {
            value = num % 10;
            for (ctr = 1; ctr <= 5; ctr++) {
                System.out.print(value * ctr + " ");
            }
        } else {
            value = (num % 10) * (-1);
            for (ctr = 1; ctr <= 10; ctr++) {
                System.out.print(value * ctr + " ");
            }
        }

    }
}

num = int(input())
if num > 0:
unit = num%10
for ctr in range(1, 6):
print(ctr*unit, end = " ")
else:
unit = (num*-1)%10
for ctr in range(1, 11):
print(ctr*unit, end = " ")

#include <iostream>
using namespace std;

int main()
{
    int num, ctr, value;
    cin >> num;
    if(num > 0)
    {
        value = num % 10;
        for(ctr = 1; ctr <= 5; ctr++)
        {
            cout << (value * ctr) << " ";
        }
    }
    else
    {
        value = (num % 10) * (-1);
        for(ctr = 1; ctr <= 10; ctr++)
        {
            cout << (value * ctr) << " ";
        }
    }
    return 0;
}