The program must accept an integer N as the input. The program must compress the integer N by concatenating the digital sum of every two consecutive digits. Then the program must print the modified value of N as the output.

Boundary Condition(s): 10 <= N <= 10^9

**Input Format:**

The first line contains the value of N.

**Output Format:**

The first line contains the modified value of N.

**Example Input/Output 1:**

**Input:**

208914

**Output:**

28815

**Explanation:**

The digital sum of 2 and 0 is 2 The digital sum of 0 and 8 is 8

The digital sum of 8 and 9 is 8

The digital sum of 9 and 1 is 1 The digital sum of 1 and 4 is 5 Hence the output is 28815

**Example Input/Output 2:Input**

1234

**Output: **

357

```
#include<stdio.h>
int main()
{
long int n;
scanf("%ld",&n);
int k=0;
int a[10000000];
while(n>0)
{
a[k]=n%10;
n/=10;
k++;
}
k--;
int m,o;
for(;k>=1;k--)
{
m=a[k]+a[k-1];
if(m>9)
{
o=m%10;
m/=10;
o=o+m;
m=o;
}
printf("%d",m);
}
}
```