Given two integers M and N as input, the program must apply the bitwise AND operation for the odd numbers between M and N(inclusive) as S1 and apply the bitwise OR operation for the even numbers between M and N(inclusive) as S2. Finally, XOR the bits of S1 and S2 and print it.

**Boundary Condition(s):**

1 <= M < N

M < N <=999999

**Input Format:**

The first line contains the M and N value separated by space.

**Output Format:**

The first line contains the integer value.

**Example Input/Output 1:**

Input:

3 6

Output:

7

Explanation :

By applying bitwise AND operation for 3 and 5 is 1, bitwise OR operation for 4 and 6 is 6, and bitwise XOR operation for 1 and 6 is 7

**Example Input/Output 2:**

Input:

10 16

Output:

23

```
#include<stdio.h>
#include <stdlib.h>
int main()
{
int m,n;
scanf("%d%d",&m,&n);
int s1=0,s2=0;
for(int i=m;i<=n;++i){
if(i%2==0){
s2=s2|i;
}
else{
s1=s1==0 ? i : i& s1;
}
}
printf("%d",s1^s2);
return 0;
}
```

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